A Sample Of 100 Clients Of An Exercise Facility Was Selected. Let X- The Number Of Days Per Week That A Randomly Selected Client Uses The Ex

Question

A Sample Of 100 Clients Of An Exercise Facility Was Selected. Let X- The Number Of Days Per Week That A Randomly Selected Client Uses The Exercise Facility X | Frequency | 1 15 2 30 3 28 4 1O Find The Number That Is 1.5 Standard Deviations BELOw The Mean. (Round Your Answer To Three Decimal Places.)

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Phúc Điền 3 years 2021-07-20T15:07:00+00:00 1 Answers 66 views 0

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  1. Neala
    0
    2021-07-20T15:08:30+00:00
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    Answer: 1.013

    Step-by-step explanation:

    Given the following data :

    X_______f___fx___fx²

    1_______15__15___15

    2______30__60__120

    3______28__84__252

    4______10__40___160

    ______ 83__199__547

    Number that is 1.5 standard deviations below the mean :

    Mean(m) :

    Σfx /Σf

    (15 + 30 + 28 + 10) / 83

    = 199 / 83

    = 2.3976

    Standard deviation(s) :

    Sqrt[(Σfx² – (Σfx)²/Σf) /Σf-1]

    sqrt[(547 – (199)²/83) / 83 – 1]

    sqrt[(547 – (39601/83) / 82]

    sqrt[(547 – 477.12) / 82]

    sqrt(0.8522)

    Standard deviation = 0.9231

    1.5 standard deviations below the mean:

    Mean – 1.5(standard deviation)

    2.3976 – 1.5(0.9231)

    2.3976 -1.38465

    = 1.01295

    = 1.013

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