## A runner is traveling with an initial velocity of 0.3 m/s in the positive direction accelerates at a constant rate of 0.4m/s^2 for a time of

Question

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## Answers ( )

Answer:1.1 m/sExplanation:Applying,

v = u+at………….. Equation 1

Where v = final velocity, u = initial velocity, a = acceleration, t = time.

From the question,

Given: u = 0.3 ms, a = 0.4 m/s², t = 2 seconds

Substitute these values into equation 1

v = 0.3+0.4(2)

v = 0.3+0.8

v = 1.1 m/s

Hence the velocity at the end of 2 seconds is 1.1 m/s