A rocket is launched from the surface of Earth with a speed v0 that will allow the rocket to escape the gravitational field of Earth. The sa

Question

A rocket is launched from the surface of Earth with a speed v0 that will allow the rocket to escape the gravitational field of Earth. The same rocket is now launched from a different planet with the same mass as Earth and four times the radius of Earth. Which of the following is a correct expression for the escape speed from the surface of the new planet?
a. 0.5V.
b. 2V0
c. 0.25v.
d. 0.71V.
e. Vo

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Khánh Gia 3 years 2021-08-12T13:25:28+00:00 1 Answers 1 views 0

Answers ( )

  1. thaiduong
    0
    2021-08-12T13:26:51+00:00
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    Answer:

    option ( a ) is correct .

    Explanation:

    Escape velocity on the earth = √ ( 2 GM / R )

    where G is universal gravitational constant , M is mass of the earth and R is radius .

    V₀ = √ ( 2 GM / R )

    escape velocity on the planet where mass is equal is earth’s mass and radius is 4 times that of the earth

    Radius of the planet = 4 R

    escape velocity of planet = √ ( 2 GM / 4R )

    = .5 x √ ( 2 GM / R )

    = .5 V₀

    option ( a ) is correct .

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