A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equa

Question

A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation. Using the equation, what height was the rocket launched from? y=-16x^2+57x+32

in progress 0
Mộc Miên 1 year 2021-09-04T05:45:33+00:00 1 Answers 16 views 0

Answers ( )

  1. Helga
    0
    2021-09-04T05:47:17+00:00
    Reply

    9514 1404 393

    Answer:

      32 feet

    Step-by-step explanation:

    0 seconds after launch, the rocket is still sitting on the tower. Its height is…

      y = -16(0^2) +57(0) +32

      y = 0 + 0 + 32 = 32

    The rocket was launched from a tower 32 feet high.

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )