Share
A ray in oil (n = 1.52) reaches a boundary with water (n = 1.33) at 55.9 deg. Does it reflect internally or refract into the air?
Question
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
Answers ( )
Answer:
Ray reflects internally
Explanation:
Given:
Ray in oil (n1) = 1.52
Ray in water (n2) = 1.33
θ = 55.9°
Computation:
Step 1 . Find critical angel(θc)
Sinθc/Sin90° = Ray in water / Ray in oil
Sinθc/1 = 1.33/1.52
θc = 61°
Since, θ = 55.9° is smaller than θc = 61°
So, Ray reflects internally.
Answer: refracts it
Explanation: i used the answer on acellus
and it was wrong