a quadratic function that fits the points (0,5) (2,3) (4,9)

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a quadratic function that fits the points (0,5) (2,3) (4,9)

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Xavia 1 year 2021-07-20T21:44:09+00:00 1 Answers 14 views 0

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    2021-07-20T21:45:24+00:00

    Answer:

    Step-by-step explanation:

    y=ax^2+bx+c we are given point (0,5) so if x=0, y=c, so c=5. We have two other points

    (2,3)(4,9) which gives us

    4a+2b+5=3 and 16a+4b+5=9

    Subtracting twice the first from the second

    16a+4b+5-8a-4b-10=9-6

    8a-5=3

    8a=8, so a=1, so using 4a+2b+5=3 we get

    4(1)+2b+5=3

    2b+9=3

    2b=-6

    b=-3 so our quadratic is

    y=x^2-3x+5

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