A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel? A) 15

Question

A projectile is launched with an initial velocity of 60.0 m/s at an angle of 30.0° above the horizontal. How far does it travel?
A) 152 m
B) 160 m
C) 184 m
D) 318 m

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Nem 2 weeks 2021-08-30T21:28:57+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-30T21:30:12+00:00

    Answer:

    D

    Explanation:

    The range is how far the projectile can go;

    R = U^2sin2A/g

    Where U is the initial velocity

    A is the angle of inclination

    =60^2sin2(30)/10 = 3600 sin60 / 10

    = 311.8m

    The exact answer should 312m

    0
    2021-08-30T21:30:18+00:00

    Answer:

    Explanation: The initial velocity has two component v x  and v y. The initial velocity in direction of y is given.

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