A projectile is launched at ground level with an initial speed of 53.0 m/s at an angle of 35.0° above the horizontal. It strikes a target ab

Question

A projectile is launched at ground level with an initial speed of 53.0 m/s at an angle of 35.0° above the horizontal. It strikes a target above the ground 2.50 seconds later. What are the x and y distances from where the projectile was launched to where it lands?

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Philomena 1 year 2021-08-31T01:32:19+00:00 1 Answers 5 views 0

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    2021-08-31T01:33:54+00:00

    Answer:

    x = 108.5 m      y = 45.37 m,  

    Explanation:

    This is a projectile launching exercise, the horizontal distance it reaches is called the range and can be found by the expression

               x = v₀ₓ t

               

    the initial hairiness is

              v₀ₓ = v₀ cos θ

               

               x = v₀ cos θ  t

      let’s calculate

               x = 53 cos 35 2.50

               x = 108.5 m

    the height of the projectile can be calculated with

                y =v₀ t – ½ g t²

                 y = vo sin tea t – ½ g t²

                y = 53 sin 35 2.50 – ½ 9.8 2.5²

                y = 45.37 m

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