A projectile is fired horizontally from a gun that is 58.0 m above flat ground, emerging from the gun with a speed of 170 m/s. (a) How long

Question

A projectile is fired horizontally from a gun that is 58.0 m above flat ground, emerging from the gun with a speed of 170 m/s. (a) How long does the projectile remain in the air

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Ngọc Diệp 5 years 2021-07-14T19:22:50+00:00 1 Answers 17 views 0

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  1. Ladonna
    0
    2021-07-14T19:23:58+00:00
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    Answer:

    t = 3.44 s

    Explanation:

    We are given;

    Fired from rest, and so; u = 0 m/s

    Final speed; v = 170 m/s

    Height above flat ground; y_o = 58 m

    Height at starting point; y = 0 m

    Thus, from Newton’s equation of motion, we have;

    y – y_o = ut – ½gt²

    (since it’s motion is against gravity)

    Plugging in the relevant values, we have;

    0 – 58 = 0 – (½ × 9.8 × t²)

    -58 = -4.9t²

    t² = 58/4.9

    t = √(58/4.9)

    t = 3.44 s

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