A portable music player, operating with four 1.5 V cells connected in series, provides a resistance of 15 000 Ω. What amount of current is f

Question

A portable music player, operating with four 1.5 V cells connected in series, provides a resistance of 15 000 Ω. What amount of current is flowing through the music player?

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Vodka 4 years 2021-07-13T12:35:15+00:00 1 Answers 6 views 0

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  1. trungdung22
    0
    2021-07-13T12:36:43+00:00
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    Answer:

    Explanation:

    Given that,

    A portable music player is operating with 4 cell batteries connected in series, and each cell has a P.D of 1.5V.

    Then,

    Total potential difference is

    P.D_total = V1 + V2 + V3 + V4

    P.D_total = 1.5 + 1.5 + 1.5 + 1.4

    P.D_total = 6V.

    The music player provides a resistance of 15,000Ω

    R = 15,000Ω

    We want to find the current (I) flowing through the music player?

    Using ohms law

    V = IR

    Where

    V is the potential difference

    I is the current

    R is the resistance

    Therefore,

    I = V/R

    I = 6 / 15,000

    I = 4 × 10^-4 A

    I = 0.4 × 10^-3 A

    I = 0.4 mA.

    So, 0.4mA is passing through the music player

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