## A point charge of +3.0 X 10-7 coulomb is placed 2.0 X 10-2 meter from a second point charge of +4.0 X 10-7 coulomb. What is the magnitude of

Question

A point charge of +3.0 X 10-7 coulomb is placed 2.0 X 10-2 meter from a second point charge of +4.0 X 10-7 coulomb. What is the magnitude of the electrostatic force on the charges?

A. 6.0 X 10-12 N

B. 3.0 X 10-10 N

C. 5.4 X 10-2 N

D. 2.7 N

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Physics
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2021-07-22T14:58:38+00:00
2021-07-22T14:58:38+00:00 1 Answers
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## Answers ( )

Answer:D. 2.7 NExplanation:Applying

F = kq’q/r²……………. Equation 1

Where F = force, k = coulomb’s constant, q’ = first charge, q = second charge, r = distance between the charge

From the question,

Given: q’ = +3.0×10⁻⁷ C, q = +4.0×10⁻⁷C, r = 2.0×10⁻² m

Constant: k = 8.98×10⁹ Nm²/C²

Substitute these values into equation 1

F = ( +3.0×10⁻⁷)(+4.0×10⁻⁷)(8.98×10⁹)/(2.0×10⁻²)²

F = 26.94×10⁻¹ N

F = 2.694 N

F ≈ 2.7 N