A point charge of +3.0 X 10-7 coulomb is placed 2.0 X 10-2 meter from a second point charge of +4.0 X 10-7 coulomb. What is the magnitude of

Question

A point charge of +3.0 X 10-7 coulomb is placed 2.0 X 10-2 meter from a second point charge of +4.0 X 10-7 coulomb. What is the magnitude of the electrostatic force on the charges?
A. 6.0 X 10-12 N
B. 3.0 X 10-10 N
C. 5.4 X 10-2 N
D. 2.7 N

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Linh Đan 1 week 2021-07-22T14:58:38+00:00 1 Answers 3 views 0

Answers ( )

    0
    2021-07-22T15:00:22+00:00

    Answer:

    D. 2.7 N

    Explanation:

    Applying

    F = kq’q/r²……………. Equation 1

    Where F = force, k = coulomb’s constant, q’ = first charge, q = second charge, r = distance between the charge

    From the question,

    Given: q’ = +3.0×10⁻⁷ C, q = +4.0×10⁻⁷C, r = 2.0×10⁻² m

    Constant: k = 8.98×10⁹ Nm²/C²

    Substitute these values into equation 1

    F = ( +3.0×10⁻⁷)(+4.0×10⁻⁷)(8.98×10⁹)/(2.0×10⁻²)²

    F = 26.94×10⁻¹ N

    F = 2.694 N

    F ≈ 2.7 N

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