A pipe has a length of 1.29 m. Determine the frequency of the first harmonic if the pipe is open at each end. The velocity of sound in air i

Question

A pipe has a length of 1.29 m. Determine the frequency of the first harmonic if the pipe is open at each end. The velocity of sound in air is 343 m/s. Answer in units of Hz.

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Hồng Cúc 5 months 2021-09-02T18:24:15+00:00 2 Answers 10 views 0

Answers ( )

    0
    2021-09-02T18:25:25+00:00

    Answer:

    132.95 Hz.

    Explanation:

    Given:

    v = 343 m/s

    L = 1.29 m.

    Since the pipe is open at both ends,

    L = λ/2

    λ = v/f = 2L

    = 2 × 1.29

    = 2.58 m

    f = 343/2.58

    = 132.95 Hz.

    0
    2021-09-02T18:26:06+00:00

    Answer:

    265.9Hz

    Explanation:

    In an open pipe, both ends of the pipes are opened. The fundamental frequency in an open pipe is expressed as fo = V/2L where;

    f is the frequency of the wave

    V is the velocity of the wave = 343m/s

    L is the length of the pipe = 1.29m

    Substituting the value to get the fundamental frequency in the open pipe we have;

    Fo = 343/2(1.29)

    Fo = 343/2.58

    Fo = 132.95Hz

    Harmonics are integral multiples of the fundamental frequency e.g 2fo, 3fo, 4fo, 5fo…

    The first harmonic in the open pipe will be f1 = 2fo

    Since f1 =2(132.95)

    f1 = 265.9Hz

    The frequency of the first harmonic if the pipe is open at each end is 265.9Hz

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