A ping-pong ball weighs 0.025 N. The ball is placed inside a cup that sits on top of a vertical spring. If the spring is compressed 0.055 m

Question

A ping-pong ball weighs 0.025 N. The ball is placed inside a cup that sits on top of a vertical spring. If the spring is compressed 0.055 m and released, the maximum height above the compressed position that the ball reaches is 2.84 m. Neglect air resistance and determine the spring constant.

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Farah 6 months 2021-07-30T15:36:13+00:00 1 Answers 53 views 0

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    2021-07-30T15:37:30+00:00

    Answer:

    Explanation:

    The energy stored in the spring is used to throw the ball upwards . Let the height reached be h

    stored energy of spring = 1/2 k y² , k is spring constant and y is compression created in the spring

    stored energy of spring = potential energy of the ball

    1/2 k y² = mgh , m is mass of the ball , h is height attained by ball

    .5 k x .055² = .025  x 2.84

    .0015125 k = .071

    k = .071 / .0015125

    = 46.9 N / m .

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