A ping-pong ball weighs 0.025 N. The ball is placed inside a cup that sits on top of a vertical spring. If the spring is compressed 0.055 m and released, the maximum height above the compressed position that the ball reaches is 2.84 m. Neglect air resistance and determine the spring constant.
Answer:
Explanation:
The energy stored in the spring is used to throw the ball upwards . Let the height reached be h
stored energy of spring = 1/2 k y² , k is spring constant and y is compression created in the spring
stored energy of spring = potential energy of the ball
1/2 k y² = mgh , m is mass of the ball , h is height attained by ball
.5 k x .055² = .025 x 2.84
.0015125 k = .071
k = .071 / .0015125
= 46.9 N / m .