A pilot flies her route in two straight-line segments. The displacement vector A for the first segment has a magnitude of 243 km and a direc

Question

A pilot flies her route in two straight-line segments. The displacement vector A for the first segment has a magnitude of 243 km and a direction 30.0o north of east. The displacement vector for the second segment has a magnitude of 178 km and a direction due west. The resultant displacement vector is R = A + B and makes an angle ? with the direction due east. Using the component method, find (a) the magnitude of R and (b) the directional angle ?.
(a) R = km
(b) ? = degrees

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Ngọc Diệp 4 years 2021-07-13T01:38:54+00:00 1 Answers 2 views 0

Answers ( )

  1. Ladonna
    0
    2021-07-13T01:40:51+00:00
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    Answer:

    a) R=126Km

    b) \theta=74.6\textdegree

    Explanation:

    From the question we are told that:

    1st segment

    243km at Angle=30

    2nd segment

    178km West

    Resolving to the X axis

    F_x=243cos30+178

    F_x=33.44Km

    Resolving to the Y axis

    F_y=243sin30+178sin0

    R=\sqrt{F_y^2+F_x^2}

    F_y=121.5Km

    Therefore

    Generally the equation for Directional Angle is mathematically given by

    \theta=tan^{-1}\frac{F_y}{F_x}

    \theta=tan^{-1}\frac{121.5}{33.44}

    \theta=74.6\textdegree

    Generally the equation for Magnitude is mathematically given by

    R=\sqrt{F_y^2+F_x^2}

    R=\sqrt{33.44^2+121.5^2}

    R=126Km

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )