A pillow is thrown downward with an initial speed of 6 m/s. After 4 seconds, the pillow’s velocity is m/s. (g= -9.8m/s2) July 20, 2021 by Verity A pillow is thrown downward with an initial speed of 6 m/s. After 4 seconds, the pillow’s velocity is m/s. (g= -9.8m/s2)
Given : Initial velocity, u = -6 m/s. Time taken, t = 4 seconds. Acceleration due to gravity, [tex]g = -9.8\ m/s^2[/tex].( Here negative sign means downward direction ) To Find : Velocity after 4 seconds. Solution : By equation of motion. v = u + at Here , a = g. v = u + gt v = -6 + (-9.8)×4 v = -6 + (-39.2) v = -45.2 m/s Therefore, velocity after 4 seconds is -45.2 m/s. Hence, this is the required solution. Reply
Given :
Initial velocity, u = -6 m/s.
Time taken, t = 4 seconds.
Acceleration due to gravity, [tex]g = -9.8\ m/s^2[/tex].( Here negative sign means downward direction )
To Find :
Velocity after 4 seconds.
Solution :
By equation of motion.
v = u + at
Here , a = g.
v = u + gt
v = -6 + (-9.8)×4
v = -6 + (-39.2)
v = -45.2 m/s
Therefore, velocity after 4 seconds is -45.2 m/s.
Hence, this is the required solution.