A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.What is the speci

Question

A piece of unknown solid substance weighs 437.2 g, and requires 8460 J to increase its temperature from 19.3 °C to 68.9 °C.What is the specific heat of the substance?

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Thiên Ân 1 year 2021-09-04T17:07:06+00:00 1 Answers 69 views 0

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    2021-09-04T17:08:35+00:00

    Answer:

    0.3832

    Explanation:

    Givens

    m = 437.2 grams

    c = ?

    delta t = 69.8 – 19.3

    H = 8460 J

    Formula

    H = m*c*Δt

    Solution

    8460 = 437.2 * c * (69.8 – 19.3)

    8460 = 437.2 * c * 50.5

    8460 = 22078.6 * c

    c = 8460 / 22078,6

    c = .3832 J / (oC * gr)

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