A person holding a lunch bag is moving upward in a hot air balloon at a constant speed of 7.7 m/s . When the balloon is 21 m above the groun

Question

A person holding a lunch bag is moving upward in a hot air balloon at a constant speed of 7.7 m/s . When the balloon is 21 m above the ground, she accidentally releases the bag. Part A What is the speed of the bag just before it reaches the ground

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Linh Đan 6 months 2021-07-29T10:00:26+00:00 1 Answers 46 views 0

Answers ( )

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    2021-07-29T10:02:12+00:00

    Answer:

    The speed of the bag just before it reaches the ground is 21.71 m/s.

    Explanation:

    The speed of the bag can be found using the following equation:

     v_{f}^{2} = v_{0}^{2} - 2gy

    Where:

    v_{f} is the final speed =?

    v_{0} is the initial speed = 7.7 m/s

    g: is the gravity = 9.81 m/s²

    y: is the height = 21 m

    v_{f}^{2} = v_{0}^{2} - 2gy = (7.7 m/s)^{2} - 2*9.81 m/s^{2}*(-21 m) = 471.31 m^{2}/s^{2}

    v_{f} = 21.71 m/s

    Therefore, the speed of the bag just before it reaches the ground is 21.71 m/s.

    I hope it helps you!    

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