A pendulum that has a period of 2.67000 s and that is located where the acceleration due to gravity is 9.77 m/s2 is moved to a location wher

Question

A pendulum that has a period of 2.67000 s and that is located where the acceleration due to gravity is 9.77 m/s2 is moved to a location where it the acceleration due to gravity is 9.81 m/s2. What is its new period? (Enter your answer in seconds and to at least 5 decimal places.)

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Thiên Ân 4 weeks 2021-08-17T12:55:41+00:00 1 Answers 3 views 0

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    2021-08-17T12:57:39+00:00

    Answer:

    Explanation:

    Expression for time period of pendulum is given as follows

    T=2\pi\sqrt{\frac{l}{g} }

    where l is length of pendulum and g is acceleration due to gravity .

    Putting the given values for first place

    2.67=2\pi\sqrt{\frac{l}{9.77} }

    Putting the values for second place

    T=2\pi\sqrt{\frac{l}{9.81} }

    Dividing these two equation

    \frac{T}{2.67} =\sqrt{\frac{9.77}{9.81} }

    T = 2.66455 s.

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