A pendulum is made by letting a 4 kg mass swing at the end of a string that has a length of 1.5 meter. The maximum angle that the string mak

Question

A pendulum is made by letting a 4 kg mass swing at the end of a string that has a length of 1.5 meter. The maximum angle that the string makes with the vertical is 30 degrees (in both directions). What is the change in the potential energy of the mass as it moves from the lowest point to the highest point of its path?

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Philomena 4 months 2021-09-05T00:51:44+00:00 1 Answers 12 views 0

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    2021-09-05T00:53:30+00:00

    Answer:

    Approximately 7.8\; \rm J.

    Explanation:

    The change in the gravitational potential energy of the pendulum is directly related to the change in its height.

    Refer to the sketch attached. The pendulum is initially at \rm P_2. Its highest point is at P_1. The length of segment \rm BP_2 gives the change in its height.

    The lengths of \rm AP_1 and \rm AP_2 are simply the length of the string, 1.5\; \rm m. To find the length of \rm BP_2, start by calculating the length of \rm AB.

    \rm AB forms a leg in the right triangle \rm \triangle AP_1B. Besides, it is adjacent to the 30^\circ angle \rm P_1\hat{A}B. Its length would be:

    \rm AB = 1.5 \times \cos(30^\circ) \approx 1.30\; \rm m.

    The length of \rm BP_2 would thus be

    \rm BP_2 = AP_2 - AB = 1.5 - 1.30 \approx 0.20\; \rm m.

    The change in gravitational potential energy can be found with the equation

    \Delta \mathrm{GPE} = m \cdot g \cdot \Delta h. In this equation,

    • m is the mass of the object,
    • g \approx 9.81\; \rm N \cdot kg^{-1} near the surface of the earth, and
    • \Delta h is the change in the object’s height.

    In this case, m = 4\; \rm kg and \Delta h \approx 0.20\; \rm m. Therefore:

    \Delta \mathrm{GPE} = 4 \times 9.81 \times 0.20 \approx 7.8\; \rm J.

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