A pendulum has a 0.35\ \text{kg}0.35 kg0, point, 35, space, start text, k, g, end text mass oscillating at a small angle from a light string

Question

A pendulum has a 0.35\ \text{kg}0.35 kg0, point, 35, space, start text, k, g, end text mass oscillating at a small angle from a light string of length 1.0\ \text{m}1.0 m1, point, 0, space, start text, m, end text. What is the frequency of oscillation?

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Helga 2 weeks 2021-08-29T18:50:28+00:00 1 Answers 0 views 0

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    2021-08-29T18:52:24+00:00

    Answer:

    The frequency of oscillation of the simple pendulum is 0.49 Hz.

    Explanation:

    Given that,

    Mass of the simple pendulum, m = 0.35 kg

    Length of the string to which it is attached, l = 1 m

    We need to find the frequency of oscillation. The frequency of oscillation of the simple pendulum is given by :

    f=\dfrac{1}{2\pi}\sqrt{\dfrac{g}{l}} \\\\f=\dfrac{1}{2\pi}\sqrt{\dfrac{9.8}{1}} \\\\f=0.49\ Hz

    So, the frequency of oscillation of the simple pendulum is 0.49 Hz. Hence, this is the required solution.

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