A pebble falls of a cliff at a height of 256 ft. If the equation for the height as a function is h(t)=-16^2 + initial height where t is time

Question

A pebble falls of a cliff at a height of 256 ft. If the equation for the height as a function is h(t)=-16^2 + initial height where t is time in seconds and h(t) is height in feet, how many seconds will it take for the pebble to hit the ground?

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MichaelMet 2 months 2021-07-30T22:09:28+00:00 1 Answers 1 views 0

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    2021-07-30T22:10:39+00:00

    Answer:

    After 4secs

    Step-by-step explanation:

    Given the function of the height expressed as;

    h(t)=-16^2 + initial height

    If initial height = 256, then;

    h(t) = -16t^2 + 256t

    The pebble will hot the ground at when h(t) = 0

    Substitute

    0 = -16t^2 + 256t

    16t^2 = 256

    t^2 = 256/16

    t^2 = 16

    t = 4

    Hence the pebble will hit the ground after 4secs

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