A particle travels horizontally between two parallel walls separated by 18.4 m. It moves toward the opposing wall at a constant rate of 9.5

Question

A particle travels horizontally between two parallel walls separated by 18.4 m. It moves toward the opposing wall at a constant rate of 9.5 m/s. Also, it has an acceleration in the direction parallel to the walls of 3.7 m/s 2 . 18.4 m 3.7 m/s 2 9.5 m/s What will be its speed when it hits the opposing wall? Answer in units of m/s

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Vodka 2 months 2021-07-22T18:30:15+00:00 1 Answers 1 views 0

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    2021-07-22T18:31:48+00:00

    Answer:

    7.18m/s

    Explanation:

    We are given that

    Distance,s=18.4 m

    Speed,v=9.5 m/s

    Acceleration,a=3.7m/s^2

    We have to find the speed when it hits the opposing wall.

    In perpendicular direction,a=0

    Time,t=\frac{distance}{speed}=\frac{18.4}{9.5}=1.94 s

    In parallel direction

    Initial velocity,u=0

    v=u+at

    Substitute the values

    v=0+3.7(1.94)=7.18 m/s

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