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A particle of mass m and charge q is released from rest in a uniform electric field Find the momentum attained by the particle after moving
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Answer:
Momentum = 2qEx/v
Explanation:
From the work – energy theorem, we know that;
Kinetic energy = work done
Now, formula for both are;
Kinetic energy = ½mv²
Work done = qEx
Where;
m is mass
v is velocity
q is charge
E is Electric field
x is distance covered.
Thus;
½mv² = qEx – – – – (eq 1)
Now, momentum formula is;
p = mv
Let’s rewrite the left hand side of equation 1 to reflect p = mv. Thus;
½v(mv) = qEx
½vp = qEx
p = 2qEx/v