a particle covers one fourth of its distance with speed v and remaining three fourth with speed 2v. the average speed of particle is:1.8/5v,

Question

a particle covers one fourth of its distance with speed v and remaining three fourth with speed 2v. the average speed of particle is:1.8/5v,2.3/2v,3.4/3v,4.7/5v

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Eirian 6 months 2021-07-17T12:29:27+00:00 2 Answers 3 views 0

Answers ( )

    0
    2021-07-17T12:30:43+00:00

    Answer: 1. \frac{8v}{5}

    Explanation: Speed is a variable in Physics defined by the rate at which an object go through a distance. It can be calculated as:

    speed=\frac{distance}{time}

    A fourth of distance with speed v takes:

    speed=\frac{distance}{time}

    time=\frac{distance}{speed}

    time=\frac{1}{4v}

    The rest of the distance with speed 2v takes:

    time=\frac{3}{4*2v}

    time=\frac{3}{8v}

    Average speed is given by:

    average=\frac{distance_{traveled}}{time_{travel}}

    Total time to cover the distance:

    time=\frac{1}{4v}+\frac{3}{8v}

    time=\frac{2+3}{8v}

    time=\frac{5}{8v}

    Total distance traveled:

    d=\frac{1}{4} +\frac{3}{4}

    d = 1

    average = 1 ÷ \frac{5}{8v}

    average=\frac{8v}{5}

    The average speed of particle is 8/5v.

    0
    2021-07-17T12:30:57+00:00

    Answer:

    Speed = \frac{8v}{5}

    Explanation:

    Given

    Speeds: v\ and\ 2v

    Required

    Determine the average speed

    First, we need to determine the time spent on the journey

    Time = Distance/Speed

    For the first \frac{1}{4}th

    T_1 =  \frac{1}{4}/v

    T_1 =\frac{1}{4v}

    For the next \frac{3}{4}th

    T_2 = \frac{3}{4}/2v

    T_2 = \frac{3}{8v}

    Total\ Time = T_1 +T_2

    T = \frac{1}{4v} + \frac{3}{8v}

    T = \frac{2+3}{8v}

    T = \frac{5}{8v}

    Average Speed is then calculated as thus:

    Speed = Distance/Time

    Speed = (\frac{1}{4} + \frac{3}{4})/\frac{5}{8v}

    Speed = (\frac{1+3}{4})/\frac{5}{8v}

    Speed = (\frac{4}{4})/\frac{5}{8v}

    Speed = 1/\frac{5}{8v}

    Speed = 1 * \frac{8v}{5}

    Speed = \frac{8v}{5}

    Hence;

    Option 1 answers the question

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