A particle (charge 7.5 µC) is released from rest at a point on the x axis, x = 10 cm. It begins to move due to the presence of a 2.0-µC char

Question

A particle (charge 7.5 µC) is released from rest at a point on the x axis, x = 10 cm. It begins to move due to the presence of a 2.0-µC charge which remains fixed at the origin. What is the kinetic energy of the particle at the instant it passes the point x = 1.0 m?

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Ngọc Hoa 4 weeks 2021-08-19T12:54:56+00:00 1 Answers 0 views 0

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    2021-08-19T12:56:43+00:00

    Answer:

    1.215J

    Explanation:

    Using the law of energy conservation, the potential energy is equal to the kinetic energy of the particle during motion:

    U_1=_qV

    #the V of the 2.0-µC is expressed as:

    V=\frac{1}{4\pi \epsilon_o r}

    We substitute the given values from the question:

    ##When the moving charge reaches 0.1meter the energy becomes

    U_1=7.5\times 10^{-6}\times \frac{2.0\times10^{-6}}{4\pi 8.85\times 10^{-12}\times 0.1\\}\\=1.35J

    #When the moving charge reaches 1.0 meter the energy becomes

    U_2=7.5\times 10^{-6}\times \frac{2.0\times10^{-6}}{4\pi 8.85\times 10^{-12}\times 1.0}\\\\=0.135J

    Hence, the change in energy is U_1-U_2=1.35-0.135=1.215J

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