A parametric equation of a curve are x=e^[2t] and y=[t^2][e^(-1)] -1 Show that the tangent to the curve at the point (1,-1) is p

Question

A parametric equation of a curve are x=e^[2t] and y=[t^2][e^(-1)] -1

Show that the tangent to the curve at the point (1,-1) is parallel to the x – axis and find the exact co-ordinates of the other point on the curve at which the tangent is parallel to the x-axis

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Edana Edana 2 weeks 2021-08-28T09:40:26+00:00 1 Answers 0 views 0

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    2021-08-28T09:42:23+00:00

    Answer:

    Hi I just wanted to send positive vibes to you and that ily

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