## A parallel-plate capacitor is held at a potential difference of 250 V. A proton is fired toward a small hole in the negative plate with a s

Question

A parallel-plate capacitor is held at a potential difference of 250 V. A proton is fired toward a small hole in the negative plate with a speed of 3.0 x 105m/s. What is its speed when it emerges through the hole in the positive plate? (Hint: The electric potential outside of a parallel-plate capacitor is zero).Copyright © 2007, Pearson Education, Inc., Publishing as Pearson Addison-Wesley.plate capacitor is held at a potential difference of 250 V. A proton is fired toward a small hole in the negative plate with a m/s. What is its speed when it emerges through the hole in the positive plate? (Hint: The electric potential outside plate capacitor is

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13 hours 2021-07-22T00:59:11+00:00 1 Answers 0 views 0

## Answers ( )

The speed of proton when it emerges through the hole in the positive plate is .

Explanation:

Given that,

A parallel-plate capacitor is held at a potential difference of 250 V.

A A proton is fired toward a small hole in the negative plate with a speed of,

We need to find the speed when it emerges through the hole in the positive plate. It can be calculated using the conservation of energy as :

So, the speed of proton when it emerges through the hole in the positive plate is .