A normal population has mean and standard deviation . (a) What proportion of the population is greater than ? (b) What is the probability th

Question

A normal population has mean and standard deviation . (a) What proportion of the population is greater than ? (b) What is the probability that a randomly chosen value will be less than .

in progress 0
Thái Dương 6 hours 2021-07-22T11:24:40+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-22T11:26:16+00:00

    Answer:

    0.0171

    0.89158

    Step-by-step explanation:

    Given :

    μ = 60

    Standard deviation , σ = 17

    The probability that a randomly chosen score is greater than 96;

    P(Z > Zscore)

    Zscore = (score, x – μ) / σ

    Zscore = (96 – 60) / 17 = 2.118

    P(Z > 2.118) = 1 – P(Z < 2.118) = 1 – 0.9829 = 0.0171

    The probability that a randomly chosen score is less than 81;

    P(Z < Zscore)

    Zscore = (score, x – μ) / σ

    Zscore = (81 – 60) / 17 = 1.235

    P(Z < 1.235) = 0.89158

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )