## A normal population has mean and standard deviation . (a) What proportion of the population is greater than ? (b) What is the probability th

Question

A normal population has mean and standard deviation . (a) What proportion of the population is greater than ? (b) What is the probability that a randomly chosen value will be less than .

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6 hours 2021-07-22T11:24:40+00:00 1 Answers 0 views 0

## Answers ( )

1. Answer:

0.0171

0.89158

Step-by-step explanation:

Given :

μ = 60

Standard deviation , σ = 17

The probability that a randomly chosen score is greater than 96;

P(Z > Zscore)

Zscore = (score, x – μ) / σ

Zscore = (96 – 60) / 17 = 2.118

P(Z > 2.118) = 1 – P(Z < 2.118) = 1 – 0.9829 = 0.0171

The probability that a randomly chosen score is less than 81;

P(Z < Zscore)

Zscore = (score, x – μ) / σ

Zscore = (81 – 60) / 17 = 1.235

P(Z < 1.235) = 0.89158