A noise created by small earthquake at a depth of 1200m in the ocean propagates upward and eventually reaches a bird flying above, at an alt

Question

A noise created by small earthquake at a depth of 1200m in the ocean propagates upward and eventually reaches a bird flying above, at an altitude of 400m. Calculate how long it takes for the noise to reach the bird. For the seawater use E = 2.34 x 109 N/m2 , rho =1030kg/m3 , and for air, γ = 1.4, and T= 2700 K)

in progress 0
RI SƠ 7 days 2021-07-21T20:45:48+00:00 1 Answers 0 views 0

Answers ( )

    0
    2021-07-21T20:47:03+00:00

    Complete Question

    The complete question is shown on the first uploaded image

    Answer:

    The time taken is  t_f  =  2.0 \ s

    Explanation:

    Generally velocity of the noise in water is mathematically represented as

    v  =  \sqrt{ \frac{E}{\rho} }

    substituting into the variable with value given in the question

    v  =  \sqrt{ \frac{2.34 * 10^9}{1030} }

    => v  = 1507.3 \  m/s

    Generally the time taken is mathematically represented as

    t =  \frac{depth }{v}

    substituting into the variable with value given in the question

    t =  \frac{1200 }{1507.3}

    => t =  0.7961 \  s

    The velocity of the noise in air is mathematically represented as

    v_w  =  \sqrt{ \gamma  *  T  *  R}

    Here  R is  the gas constant with value  [R=286.6 m^2 /(sec^2 K) ][\tex]So        [tex]v_w  =  \sqrt{ 1.4  *  270  *  286.6}

          v_w  =  329.1 \  m/s

    The  time taken is  

           t_1 =  \frac{400}{329.1}

    =>      t_1 =  1.22 \  s

    => The  total time is mathematially represented as

                  t_f = t_1 +t =  1.22 + 0.7961     

                     t_f  =  2.0 \ s     

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )