a, x mũ 2 = 16/49 b, x mũ 2 = 36/49 c, ( x + 1/2 ) mũ 2 = 9/4 d, ( x – 2/3 ) mũ 2 = 1/8 Giúp đi nha November 16, 2020 by Acacia a, x mũ 2 = 16/49 b, x mũ 2 = 36/49 c, ( x + 1/2 ) mũ 2 = 9/4 d, ( x – 2/3 ) mũ 2 = 1/8 Giúp đi nha
`x^2=16/49` \(⇔\left[\begin{array}{l}x^2=(\dfrac{4}{7})^2\\x^2=(-\dfrac{4}{7})^2\end{array} \right.\) \(⇔\left[\begin{array}{l}x=\dfrac{4}{7}\\x=-\dfrac{4}{7}\end{array} \right.\) `x^2=36/49` \(⇔\left[\begin{array}{l}x^2=(\dfrac{6}{7})^2\\x^2=(-\dfrac{6}{7})^2\end{array} \right.\) \(⇔\left[\begin{array}{l}x=\dfrac{6}{7}\\x=-\dfrac{4}{7}\end{array} \right.\) `(x+1/2)^2=9/4` \(⇔\left[\begin{array}{l}x+\dfrac{1}{2}=\dfrac{3}{2}\\x+\dfrac{1}{2}=-\dfrac{3}{2}\end{array} \right.\) \(⇔\left[\begin{array}{l}x=1\\x=-2\end{array} \right.\) `(x-2/3)^2=1/8` \(⇔\left[\begin{array}{l}x-\dfrac{2}{3}=2\sqrt{2}\\x-\dfrac{2}{3}=-2\sqrt{2}\end{array} \right.\) \(⇔\left[\begin{array}{l}x=\dfrac{2+6\sqrt{2}}{3}\\x=\dfrac{2-6\sqrt{2}}{3}\end{array} \right.\) Reply
Đáp án: Giải thích các bước giải: a, x= (4/7)^2 b, x= (6/7)^2 Cậu vote cho tớ để tớ hỏi bài đc ko. tớ gâps lắm Reply
`x^2=16/49`
\(⇔\left[\begin{array}{l}x^2=(\dfrac{4}{7})^2\\x^2=(-\dfrac{4}{7})^2\end{array} \right.\)
\(⇔\left[\begin{array}{l}x=\dfrac{4}{7}\\x=-\dfrac{4}{7}\end{array} \right.\)
`x^2=36/49`
\(⇔\left[\begin{array}{l}x^2=(\dfrac{6}{7})^2\\x^2=(-\dfrac{6}{7})^2\end{array} \right.\)
\(⇔\left[\begin{array}{l}x=\dfrac{6}{7}\\x=-\dfrac{4}{7}\end{array} \right.\)
`(x+1/2)^2=9/4`
\(⇔\left[\begin{array}{l}x+\dfrac{1}{2}=\dfrac{3}{2}\\x+\dfrac{1}{2}=-\dfrac{3}{2}\end{array} \right.\)
\(⇔\left[\begin{array}{l}x=1\\x=-2\end{array} \right.\)
`(x-2/3)^2=1/8`
\(⇔\left[\begin{array}{l}x-\dfrac{2}{3}=2\sqrt{2}\\x-\dfrac{2}{3}=-2\sqrt{2}\end{array} \right.\)
\(⇔\left[\begin{array}{l}x=\dfrac{2+6\sqrt{2}}{3}\\x=\dfrac{2-6\sqrt{2}}{3}\end{array} \right.\)
Đáp án:
Giải thích các bước giải:
a, x= (4/7)^2
b, x= (6/7)^2
Cậu vote cho tớ để tớ hỏi bài đc ko. tớ gâps lắm