A molecule with a charge of 9 x 10-8 C is moving with a velocity of 7 x 107 m/s perpendicular to a magnetic field with a value of 0.57 Tesla

Question

A molecule with a charge of 9 x 10-8 C is moving with a velocity of 7 x 107 m/s perpendicular to a magnetic field with a value of 0.57 Tesla. What is the magnitude force (in N) on the molecule?

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Sigridomena 5 months 2021-08-18T14:40:48+00:00 1 Answers 3 views 0

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    2021-08-18T14:41:51+00:00

    Answer:

    3.591 N

    Explanation:

    Applying,

    F = Bvq…………….. Equation 1

    Where F = magnitude of force on the molecule, B = Magnetic field, v = Velocity of the molecule, q = charge of the molecule.

    From the question,

    Given: B = 0.57 Tesla, q = 9×10⁻⁸ C, v = 7×10⁷ m/s

    Substitute these values into equation 1

    F = 0.57×9×10⁻⁸×7×10⁷

    F = 35.91×10⁻¹

    F = 3.591 N

    Hence the force on the molecule is 3.591 N

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