A meteoroid is in a circular orbit 600 km above the surface of a distant planet. The planet has the same mass as Earth but has a radius that is 90 % of Earth’s (where Earth’s radius is approximately 6370 km ).The acceleration of the meteoroid due to the gravitational force exerted by the planet is most nearly
Answer:
The acceleration of the meteoroid due to the gravitational force exerted by the planet = 12.12 m/[tex]s^{2}[/tex]
Explanation:
A meteoroid is in a circular orbit 600 km above the surface of a distant planet.
Mass of the planet = mass of earth = 5.972 x [tex]10^{24}[/tex] Kg
Radius of the earth = 90% of earth radius = 90% 6370 = 5733 km
The acceleration of the meteoroid due to the gravitational force exerted by the planet = ?
By formula, g = [tex]\frac{GM}{r^{2} }[/tex]
where g is the acceleration due to the gravity
G is the universal gravitational constant = 6.67 x [tex]10^{-11}[/tex] [tex]m^{3} kg^{-1} s^{-2}[/tex]
M is the mass of the planet
r is the radius of the planet
Substituting the values, we get
g = [tex]\frac{(6.67 * 10^{-11}) (5.972 * 10^{24}) }{5733^{2} }[/tex]
g = 12.12 m/[tex]s^{2}[/tex]
The acceleration of the meteoroid due to the gravitational force exerted by the planet = 12.12 m/[tex]s^{2}[/tex]
Answer:c
Explanation: