A metal wire of resistance R is cut into eight equal pieces that are then placed together side by side to form a new cable with a length equ

Question

A metal wire of resistance R is cut into eight equal pieces that are then placed together side by side to form a new cable with a length equal to one-eight the original length. What is the resistance of this new cable

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RobertKer 1 week 2021-07-22T09:41:11+00:00 1 Answers 4 views 0

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    2021-07-22T09:42:19+00:00

    Answer:

    R / 64

    Explanation:

    Let he length of the wire is L and its resistance is R.

    The resistance of the wire is directly proportional to the length of the wire. As the wire is cut into 8 equal pieces so the resistance of small wire is R/8.

    Now they are connected in parallel.

    The equivalent resistance is given by

    \frac{1}{R_{eq}}=  8\times \frac{8}{R}

    R_{eq}=\frac{R}{64}

    Thus, the equivalent resistance of the new cable is R / 64.

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