Share

## A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal in gm which

Question

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

## Answers ( )

Answer:Explanation:Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.

Metal X can form 2 oxides (A and B).

A + B =

3gThe mass of oxygen in A is

0.72gand the mass of oxygen in B is1.16g.The mass of metal X in the two oxides will be the same because it’s the same metal.

Thus, we represent the mass of the metal in the two oxides as 2X.

2X + 0.72 + 1.16 = 3

2X + 1.88 = 3

2X = 3 – 1.88

2X = 1.12

X =

0.56Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.Thus,mass of metal (X) in 1g of oxygen in A is0.56g ⇒ 0.72g

X ⇒ 1

X = 1 × 0.56/0.72

X =

0.78 gHence, 0.78g of the metal will combine with 1g of oxygen for AAlso, mass of metal (X) in 1g of oxygen in B is

0.56g ⇒ 1.16g

X ⇒ 1g

X = 1×0.56/1.16

X =

0.48 gThus, 0.48g of the metal will combine with 1g of oxygen for B