A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal in gm which

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A metal X from two oxide A and B .3.oogm of A and B contain 0.72 and 1.16g of oxygen respectively.calculate the maases of metal in gm which combine with one gram of oxygen in each case

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Edana Edana 6 months 2021-07-14T06:30:40+00:00 1 Answers 48 views 0

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    2021-07-14T06:31:40+00:00

    Answer:

    Explanation:

    Firstly, we have to determine the mass of metal X. We can do that by interpreting the first and second statement mathematically.

    Metal X can form 2 oxides (A and B).

    A + B = 3g

    The mass of oxygen in A is 0.72g and the mass of oxygen in B is 1.16g.

    The mass of metal X in the two oxides will be the same because it’s the same metal.

    Thus, we represent the mass of the metal in the two oxides as 2X.

    2X + 0.72 + 1.16 = 3

    2X + 1.88 = 3

    2X = 3 – 1.88

    2X = 1.12

    X = 0.56

    Thus, 0.56 g of the metal combines with 0.72g of oxygen in A and 1.16 g of oxygen in B.

    Thus, mass of metal (X) in 1g of oxygen in A is

    0.56g ⇒ 0.72g

    X ⇒ 1

    X = 1 × 0.56/0.72

    X = 0.78 g

    Hence, 0.78g of the metal will combine with 1g of oxygen for A

    Also, mass of metal (X) in 1g of oxygen in B is

    0.56g ⇒ 1.16g

    X ⇒ 1g

    X = 1×0.56/1.16

    X = 0.48 g

    Thus, 0.48g of the metal will combine with 1g of oxygen for B

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