A metal, conducting cylinder of length 0.25 meters contains a total charge of 0.5 coulombs. Use Gauss’ Law to find the electric field streng

Question

A metal, conducting cylinder of length 0.25 meters contains a total charge of 0.5 coulombs. Use Gauss’ Law to find the electric field strength at a radius of 0.1 meters from the cylinder, assuming the cylinder has a radius less than 0.1 meters.

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Ngọc Khuê 2 weeks 2021-08-28T18:11:54+00:00 1 Answers 0 views 0

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    2021-08-28T18:13:19+00:00

    Answer:

    Explanation:

    Let assume that cylinder has a radius of 0.01 meters. The Gauss Law has the following form:

    \frac{Q_{enc}}{\epsilon_{o}}= E\cdot A

    The electric field considering the cylinder configuration that encloses the conducting cylinder is:

    E = \frac{Q_{enc}}{\epsilon_{o}\cdot (2\cdot \pi \cdot R \cdot L)}

    Where \epsilon_{o} is the absolute permittivity.

    E=\frac{0.5\,C}{\left(8.854\times 10^{-12}\,\frac{C^{2}}{N\cdot m^{2}} \right)\cdot (2\cdot \pi)\cdot (0.011\,m)\cdot (0.25\,m)}

    E = 3.268\times 10^{12}\,\frac{N}{C}

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