A merry-go-round accelerates from rest to 0.68 rad/s in 34 s. Assuming the merry-go-round to be uniform disk of radius 7.0 m and mass 31,000

Question

A merry-go-round accelerates from rest to 0.68 rad/s in 34 s. Assuming the merry-go-round to be uniform disk of radius 7.0 m and mass 31,000 kg. The moment of inertia of a uniform disk of mass M and radius R rotating about its axis is MR2/2. Calculate its moment of inertia.

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Thành Đạt 7 hours 2021-07-22T01:44:19+00:00 1 Answers 0 views 0

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    2021-07-22T01:45:50+00:00

    Answer:

    759500kgm²

    Explanation:

    Angular velocity (w) = 0.68rad/s

    Time (t) = 34s

    Radius (r) = 7m

    Mass (m) = 31000kg

    Moment of inertia of a circular disk (I) = Mr² / 2

    Moment of inertia (I) = (31000 * 7²) / 2

    I = 759500kgm²

    The moment of inertia of the disk is 759500kgm²

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