A mass of 50.00g hangs from a 7.00cm-long spring that is rigidly attached to a ceiling. The mass is pulled down slightly, let go, and is obs

Question

A mass of 50.00g hangs from a 7.00cm-long spring that is rigidly attached to a ceiling. The mass is pulled down slightly, let go, and is observed to make 8 round trips (up and back down) in 14.00s. What is the stiffness constant for this spring

in progress 0
Khánh Gia 3 weeks 2021-08-23T23:10:47+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-08-23T23:12:06+00:00

    Answer:

    0.645 N/M

    Explanation:

    Given

    Mass=50.00g

    We have to convert into the kg

    So Mass =0.050 Kg

    Time\ = \frac{14}{8}\ = 1.75\  sec

    We know that

    T\ =2\ PI\sqrt{\frac{M}{K} }……………………Eq(1)

    Where T= time

    and M= Mass

    K= Stiffness constant

    On squaring both side we get

    K=\frac{4\pi^{2} M}{T^{2} }….Eq(2)

    Putting the value of M ,T and π in Eq(2) we get

    K=0.645 N/M

Leave an answer

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )