A mass of 50.00g hangs from a 7.00cm-long spring that is rigidly attached to a ceiling. The mass is pulled down slightly, let go, and is obs

Question

A mass of 50.00g hangs from a 7.00cm-long spring that is rigidly attached to a ceiling. The mass is pulled down slightly, let go, and is observed to make 8 round trips (up and back down) in 14.00s. What is the stiffness constant for this spring

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Khánh Gia 4 years 2021-08-23T23:10:47+00:00 1 Answers 9 views 0

Answers ( )

  1. thaiduong
    0
    2021-08-23T23:12:06+00:00
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    Answer:

    0.645 N/M

    Explanation:

    Given

    Mass=50.00g

    We have to convert into the kg

    So Mass =0.050 Kg

    Time\ = \frac{14}{8}\ = 1.75\ sec

    We know that

    T\ =2\ PI\sqrt{\frac{M}{K} }……………………Eq(1)

    Where T= time

    and M= Mass

    K= Stiffness constant

    On squaring both side we get

    K=\frac{4\pi^{2} M}{T^{2} }….Eq(2)

    Putting the value of M ,T and π in Eq(2) we get

    K=0.645 N/M

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