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A mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of 10 cm/s, and
Question
A mass of 100 g stretches a spring 5 cm. If the mass is set in motion from its equilibrium position with a downward velocity of 10 cm/s, and if there is no damping, determine the position u of the mass at any time t. When does the mass first return to its equilibrium position
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Physics
5 months
2021-08-17T11:57:09+00:00
2021-08-17T11:57:09+00:00 1 Answers
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Answers ( )
Answer:
Explanation:
Data
mass m= 100g
Length L= 5cm
we can use:
gm-kL= 0
divide both side by m
g –
=0
where
so now
square both side
We can apply:
u(t)=Acoswt +Bsinwt
u(t)=Acos14t +Bsin14t
u(0)=0 where A=0
therefore
u(0) = Bsin14t
so now u(t)=
sin14t
so t will be:
t=
t=
t=0.22 seconds