A mass is attached to a spring of spring constant 60 N/m along a horizontal, frictionless surface. The spring is initially stretched by a fo

Question

A mass is attached to a spring of spring constant 60 N/m along a horizontal, frictionless surface. The spring is initially stretched by a force of 5.0 N on the mass and let go. It takes the mass 0.50 s to go back to its equilibrium position when it is oscillating. What is the frequency of oscillation?

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Ngọc Diệp 2 weeks 2021-07-22T08:34:46+00:00 1 Answers 5 views 0

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    2021-07-22T08:36:03+00:00

    Answer:

    0.5 Hz

    Explanation:

    If it takes 0.5s to go back to the equilibrium position, that means it would take 1 s to reach maximum compression, and 2s to go back to the initial stretching position, aka complete 1 cycle of oscillation.

    So the period is T = 2s. Then the frequency would be

    f = \frac{1}{T} = \frac{1}{2} = 0.5 Hz

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