A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min

Question

A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min at 80.0 km/h, and 60.0 min at 60.0 km/h and spends
25.0 min eating lunch and buying gas.

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Edana Edana 4 months 2021-07-17T09:15:30+00:00 1 Answers 1 views 0

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    2021-07-17T09:17:18+00:00

    Complete Question

    A man on a road trip drives a car at different constant speeds over several legs of the trip. He drives for 55.0 min at 60.0 km/h, 18.0 min at 80.0 km/h, and 60.0 min at 60.0 km/h and spends

    25.0 min eating lunch and buying gas

    What is the total distance traveled over the entire trip (in km)

    Answer:

    The value is D = 139.02 \ km

    Explanation:

    From the question we are told that

    For  t_1 =  55 min = \frac{55}{60}  =  0.917 \ h the speed is v_1 =  60 \  km/h

    For  t_2 =  18 min  = \frac{18}{60}  =  0.3 \ h the speed is v_2 =  80 \  km/h

    For  t_3 = 60 min = \frac{60}{60}  =  1 \ h the speed is v_3 =  60\  km/h

    The time taken to have lunch is t _l  = 25 \  min =  \frac{25}{60} =  0.42 \  h

    Generally the total distance traveled over the entire trip (in km) is mathematically represented as

    D = t_1 *  v_1 + t_2 * v_2 + t_3 * v_3

    =>   D = 0.917  *  60 +  0.3 * 80 +  1  * 60

    =>   D = 55.02  + 24 +   60

    =>   D = 139.02 \ km

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