A man is walking down a very long flight of steps in a stairwell. He begins at 136 feet above ground level. He walks down with a

Question

A man is walking down a very long flight of
steps in a stairwell. He begins at 136 feet
above ground level. He walks down with a
steady rate such that he gets closer to the
ground floor at a rate of 2.8 feet per second.
The man is going to exit the stairwell at the
4th floor, which is the height of 42 feet above
ground level. Let t be equal to the number of
seconds it takes for him to get to the 4th floor.
Set up and solve the equation to find the value
of t. Round your answer to the nearest tenth
of a second.

in progress 0
Verity 1 year 2021-08-31T01:47:04+00:00 1 Answers 20 views 0

Answers ( )

    0
    2021-08-31T01:48:47+00:00

    Answer:

    33.6 seconds

    Step-by-step explanation:

    if he begins at 136 feet and wants to go to 42 feet, the distance is 94 feet

    d = 94

    r = 2.8

    d = rt; solving this formula for ‘t’:

    t = d/r

    t = 94/2.8

    t = 33.6 seconds

Browse

Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )