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A lunar module weighs 12 metric tons on the surface of the Earth. How much work is done in propelling the module from the surface of the moo
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Answers ( )
Answer:
149.05J
Explanation:
Hello,
Data;
Weight = 12N
x = 80miles
Radius of the moon = 1079.4mi
W = mg
But gravity at moon = ⅙ the gravity on earth
12 = ⅙ × m
M = 2kg
Mass of the module = 2kg
K = F.x
F(x) = k / x²
2 = k / (1079.4)²
k = 2.33×10⁶
Work = ∫f.dx
work = ∫₁₀₇₉.₄¹¹⁵⁹ . (2.33×10⁶/x²).dx
Work = (-2.33×10⁶) ×(¹/₁₁₅₉ – ¹/₁₀₇₉)
work = 149.05J