A low-pressure sodium vapor lamp whose wavelength is 5.89 x 10^−7 m passes through double-slits that are 2.0 x 10^−4 m apart and produces an

A low-pressure sodium vapor lamp whose wavelength is 5.89 x 10^−7 m passes through double-slits that are 2.0 x 10^−4 m apart and produces an interference pattern whose fringes are 3.2 x 10^−3 m apart on the screen. What is the distance to the screen?

3 meters

2.7 meters

1.6 meters

1.1 meters

its literally 1.1 meters I got it right

0 thoughts on “A low-pressure sodium vapor lamp whose wavelength is 5.89 x 10^−7 m passes through double-slits that are 2.0 x 10^−4 m apart and produces an”

  1. Answer:

    Distance of the screen is approx 1.1 m

    Explanation:

    As we know that fringe width on Young’s double slit experiment is given as

    [tex]\beta = \frac{\lambda L}{d}[/tex]

    here we know that

    [tex]\beta = 3.2 \times 10^{-3}[/tex]

    [tex]\lambda = 5.89 \times 10^{-7} m[/tex]

    [tex]d = 2.0 \times 10^{-4} m[/tex]

    now we have

    [tex]3.2 \times 10^{-3} = \frac{(5.89 \times 10^{-7})L}{2.0 \times 10^{-4}}[/tex]

    [tex]L = 1.1 m[/tex]

    Reply

Leave a Comment