A loudspeaker at the origin emits a 130 Hz tone on a day when the speed of sound is 340 m/s. The phase difference between two points on the

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A loudspeaker at the origin emits a 130 Hz tone on a day when the speed of sound is 340 m/s. The phase difference between two points on the x-axis is 5.6 rad.What is the distance between these two points

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Diễm Thu 5 months 2021-08-15T04:20:55+00:00 1 Answers 12 views 0

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    2021-08-15T04:22:06+00:00

    Answer:

    distance between two points having phase difference 5.6 rad is

    Φ = 2.33 m

    Explanation:

    given

    frequency, f = 130Hz

    speed of sound in air, v = 340m/s

    distance between two crust or through with phase difference 2\pi = λ
    (wavelength)

    phase difference = 5.6 rad

    note: distance between two points having a phase difference = \frac{ \lambda }{2\pi }

    ∴ distance between two points having phase difference of 5.6 rad is = \frac{ \lambda }{2\pi } ×5.6

    Recall

    v = f × λ

    speed = frequency × wavelength

    wavelength = speed/frequency

    λ  = v/f

    λ  = 340/130 = 2.615 m

    ∴ distance between two points having phase difference 5.6 rad is = \frac{ 2.615 }{2\pi  } ×5.6 = 2.33 m

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