A line with a slope of – 5 passes through the points (3,n) and (4, – 5). What is the value of n?

Question

A line with a slope of – 5 passes through the points (3,n) and (4, – 5). What is the value of n?

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Khoii Minh 2 weeks 2021-09-02T09:00:33+00:00 2 Answers 0 views 0

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    2021-09-02T09:01:39+00:00

    Answer:

    n = 0

    Step-by-step explanation:

    slope = y2-y1/x2-x1

    so

    -5 -n / 4-3 = -5

    -5 -n /1 =-5

    -5 – n = -5

    n = 0

  1. Step-by-step explanation: To find n, plug all the given information into the slope formula, which is shown here: m = y₂ – y₁ / x₂ – x₁.

    Since our slope or m equals -5, we start

    by plugging a -5 in for m in our formula.

    Now, y₂ – y₁ would be -5 – n and x₂ –  x₁ would be 4 – 3.

    So we have -5 = -5 – n/4 – 3.

    First we would simplify 4 – 3 to get 1.

    So in our next step we have -5 = -5 – n/1.

    Now get rid of the fraction by multiplying both sides by 1

    and since multiplying anything by 1 is itself, just cancel the 1.

    So we have -5 = -5 – n.

    Add 5 to both sides to get 0 = -n.

    Divide both sides by -1 to get 0 = n.

    So the value of n is 0.

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