A line is parallel to y = 3x + 5 and intersects the point (-2, 6). What is the equation of this parallel line? Start by en

Question

A line is parallel to y = 3x + 5 and
intersects the point (-2, 6). What is
the equation of this parallel line?
Start by entering this into point-slope form.
y- [?] = [](x
](x-[]).

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RobertKer 4 years 2021-09-02T01:46:54+00:00 2 Answers 5 views 0

Answers ( )

  1. Ladonna
    0
    2021-09-02T01:47:56+00:00
    Reply

    Answer:

    • y = 3x + 12

    Step-by-step explanation:

    Parallel lines have same slope

    Given line

    • y = 3x + 5

    The line that passes through (-2, 6) and with the slope of 3 is:

    • y – y₁ = m(x – x₁)
    • y – 6 = 3(x – (-2))
    • y – 6 = 3(x + 2)

    Convert the equation into slope-intercept form:

    • y – 6 = 3x + 6
    • y = 3x + 6 + 6
    • y = 3x + 12
  2. thienthanh
    0
    2021-09-02T01:48:12+00:00
    Reply

    Answer:

    Im not like 100% sure but i think you answer is

    y-6=3[x-(-2)]

    y=6+3x+6

    y=3x+12

    And i believe that this is parallel to y

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Giải phương trình 1 ẩn: x + 2 - 2(x + 1) = -x . Hỏi x = ? ( )