A light ray propagates in Material 1 with index of refraction n 1 = 1.19 , strikes an interface, then passes into Material 2 with index of r

Question

A light ray propagates in Material 1 with index of refraction n 1 = 1.19 , strikes an interface, then passes into Material 2 with index of refraction n 2 = 1.37 . The angle of incidence at the interface is θ 1 = 31.9 °. Find the angle of refraction θ 2 .

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Khải Quang 5 months 2021-08-09T17:01:24+00:00 1 Answers 5 views 0

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    2021-08-09T17:02:26+00:00

    Answer:

        θ₂ = 27.3º

    Explanation:

    For this exercise we will use the law of refraction

             n₁ sin θ₁ = n₂ sin  θ₂

    Where we use index 1 for material 1 and index 2 for material 2

    Let’s clear

               sin θ₂ = n₁ / n₂  sin θ₁

             

    Let’s calculate

              sin θ₂ = 1.19 / 1.37 sin 31.9

              θ₂ = sin⁻¹ (0.4590)

             θ₂ = 27.3º

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