A light ray moving at a 54.3 deg angle in water (n = 1.33) hits a boundary with oil (n = 1.52). At what angle is it refracted

Question

A light ray moving at a 54.3 deg
angle in water (n = 1.33) hits a
boundary with oil (n = 1.52). At
what angle is it refracted in the oil?
(Water n = 1.33, Air n = 1.00)
(Unit = deg)​

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Thiên Ân 5 months 2021-08-27T15:18:58+00:00 1 Answers 0 views 0

Answers ( )

  1. kimcuc
    0
    2021-08-27T15:20:57+00:00
    Reply

    Answer:

    45.25^{\circ}

    Explanation:

    Applying Snell’s law

    n_1sin\theta_1 = n2*sin\theta_2\\1.33*sin(54.3) = 1.52*sin\theta_2\\sin\theta_2 = 1.33*0.81208353/1.52 = 0.71057\\\theta_2=sin^{-1} (0.71057)\\\theta_2 = 45.25^{\circ}

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