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A lens with f= 10.0 cm is held 45.0 cm from an object. What is the image distance? (Unit = cm) it is not 12 cm.
Question
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Answers ( )
Answer:
1/f = 1/u + 1/v
f=10cm
u=45cm
v=? (Image distance)
1/v = 1/f – 1/u
1/v = 1/10 – 1/45
1/v = (9-2)÷ 90
1/v = 7/90
:. v = 90/7
v=12.86cm(image distance)
Answer:
8.2 cm
Explanation:
1/f = 1/so + 1/si
1/10 = 1/45 + 1/si
1/si = 1/10 – 1/45
1/si = 9/90 – 2/90
1/si = 7/90
si = 90/7 = 12.86 cm.
since you said that the answer was not 12 them the lens must be concave with negative (minus) focal length
1/f = 1/so + 1/si
– 1/10 = 1/45 + 1/si
1/si = – 1/10 – 1/45
1/si = -9/90 – 2/90
1/si = -11/90
si = -90/11 = – 8.2 cm
– (read: minus or negative sign) indicates the image is in the same side of the object
hope its true and can help you