a lead block drops its temperature by 5.90 degrees celsius when 427 J of heat are removed from it. what is the mass of the block?(unit=kg) I

Question

a lead block drops its temperature by 5.90 degrees celsius when 427 J of heat are removed from it. what is the mass of the block?(unit=kg) IM GIVING 30 POINTS FOR THE CORRECT ANSWER

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Gerda 3 weeks 2021-09-03T17:48:42+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-09-03T17:49:42+00:00

    Answer:

    577g

    Explanation:

    Given parameters:

    Temperature change = 5.9°C

    Amount of heat lost = 427J

    Unknown:

    Mass of the block = ?

    Solution:

    The heat capacity of a body is the amount of heat required to change the temperature of that body by 1°C.

                    H =  m c Ф

      H is the heat capacity

     m  is the mass of the block

      c is the specific heat capacity

       Ф is the temperature change

    Specific heat capacity of lead is 0.126J/g°C

       m = H / m Ф

       m = \frac{427}{0.126 x 5.9}  = 577g

    Mass of the lead block is 577g

    0
    2021-09-03T17:50:01+00:00

    Answer: 0.5654

    Explanation:

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